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Use the attached spreadsheet template to complete the assignment.  Click on each of the tabs in the template to view each of the exercises.

ThanksCh 8 Ex 4

PMT472 3.2 ASSIGNMENT: WEEK 3 EXERCISES

CH. 8 EXERCISE 4

Given the network plan that follows, compute the early, late, and slack times. Using any approach you wish (e.g., trial and error), develop a loading chart for resource, electrical engineers (EE), and resource, mechanical engineers (ME).

Start
0
1

4

5

End

Legend

EE

EE

ME

ES
ID
EF

2

1

6

SL
Resource
SL

LS
DUR
LF

0
2

6

EE

ME

4

2

0
3

7

ME

EE

3

4

EE

ME

0
1
2
3
4
5
6
7
8
9
10
11
12

What is the project duration?

(Enter response)

EE

ME

0
1
2
3
4
5
6
7
8
9
10
11
12

Resource Activity Schedule (with resource constraint)

ID/RES
ES
LS
EF
LF
SL

1-EE

2-EE

3-ME

4-EE

5-ME

6-ME

7-EE

Which activities are now critical?

(Enter response)

What is the project duration now?

(Enter response)

Could something like this happen in real projects?

(Enter response)

Ch 9 Ex 1

PMT472 3.2 ASSIGNMENT: WEEK 3 EXERCISES

CH. 9 EXERCISE 1

Use the following information to compress one time unit per move using the least-cost method. Reduce the schedule until you reach the crash point of the network. For each move identify what activity or activities were crashed and the adjusted total direct cost. Note: The correct normal project duration, critical path, and total direct cost are provided. The crash cost is how much extra it will cost to crash the activity per time unit reduced. The maximum crash time is how many time units the activity can be reduced by. E.g. Activity D can be reduced by 2 time units down to 1 time unit for a total additional cost of \$120.

Activity
Crash Cost (slope)

Maximum Crash Time

Normal Time

Normal Cost

A
\$50

1

3

\$150

B
\$100

1

3

\$100

C
\$60

2

4

\$200

D
\$60

2

3

\$200

E
\$70

1

4

\$200

F
\$0

0

1

\$150

Crash Round 1

B

D

What was crashed:

Activity A was reduced by 1 day (or time unit) from 3 days to 2 days.

3

3

\$1,050

A

F

The cheapest activity to reduce is A so we reduce it by its maximum reduction of one time unit to two time units. The A-C-E-F path remains critical at 11 time units and direct costs go up to \$1,050 since it cost \$50 to crash A.

2

1

C

E

4

4

Crash Round 2

B

D

What was crashed:

(Enter response)

(Enter response)

A

F

C

E

Crash Round 3

B

D

What was crashed:

(Enter response)

(Enter response)

A

F

C

E

Crash Round 4

B

D

What was crashed:

(Enter response)

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